Step 1: Understanding the Problem

We need to print the first n terms of the Fibonacci series, where each term is the sum of the two preceding terms. The Fibonacci series starts with 0 and 1, and subsequent terms are generated by adding the two previous terms.

Step 2: Developing the Algorithm

To print the first n terms of the Fibonacci series, we can use a loop to generate each term. We’ll initialize the first two terms (0 and 1) and then iterate n-2 times to generate and print the remaining terms by adding the previous two terms.

Step 3: Writing the Python Code

Here’s the Python code to print the first n terms of the Fibonacci series:

def fibonacci(n):
    # Check if n is less than or equal to 0
    if n <= 0:
        print("Invalid input. Please enter a positive integer.")
        return

    # First two terms of the Fibonacci series
    term1 = 0
    term2 = 1

    # Print the first two terms
    print(term1, term2, end=" ")

    # Generate and print the remaining terms
    for _ in range(n - 2):
        next_term = term1 + term2
        print(next_term, end=" ")

        # Update the terms for the next iteration
        term1, term2 = term2, next_term

# Test the function
n = 10
fibonacci(n)

O/P

0 1 1 2 3 5 8 13 21 34

Step 4: Code Explanation

1. We define a function fibonacci that takes the parameter n, representing the number of terms to be printed.

2. We first check if n is less than or equal to 0. If so, we print an error message and return from the function.

3. We initialize term1 and term2 as the first two terms of the Fibonacci series (0 and 1).

4. We print the first two terms using the print function, specifying end=” ” to ensure they are printed on the same line with a space between them.

5. We use a loop that iterates n – 2 times (since the first two terms are already printed).

6. Inside the loop, we calculate the next term by adding term1 and term2 and store it in next_term.

7. We print the next_term, again using end=” ” to print it on the same line with a space.

8. We update term1 and term2 for the next iteration by assigning term2 to term1 and next_term to term2.

Step 5: Dry Run the Code

Sure! Let’s do a dry run of the code iteration-wise for n = 10:

Iteration 1:

• First term: 0
• Second term: 1
• Output: 0 1

Iteration 2:

• Next term: 1 + 0 = 1
• Output: 0 1 1

Iteration 3:

• Next term: 1 + 1 = 2
• Output: 0 1 1 2

Iteration 4:

• Next term: 1 + 2 = 3
• Output: 0 1 1 2 3

Iteration 5:

• Next term: 2 + 3 = 5
• Output: 0 1 1 2 3 5

Iteration 6:

• Next term: 3 + 5 = 8
• Output: 0 1 1 2 3 5 8

Iteration 7:

• Next term: 5 + 8 = 13
• Output: 0 1 1 2 3 5 8 13

Iteration 8:

• Next term: 8 + 13 = 21
• Output: 0 1 1 2 3 5 8 13 21

Iteration 9:

• Next term: 13 + 21 = 34
• Output: 0 1 1 2 3 5 8 13 21 34

Iteration 10:

• No more iterations since n = 10 has been reached.

The final output will be: 0 1 1 2 3 5 8 13 21 34.

Each iteration calculates the next term by adding the previous two terms and appends it to the output. The process continues until the desired number of terms (n) is reached.

Feel free to modify and experiment with the code to understand it better and explore other variations or optimizations.