Note : Solutions will be uploaded in upcoming days.

**1. Consider two tumblers, the first containing one litre of water. Suppose you take one spoon of water out of the first tumbler and pour it into the second tumbler and after which you take one spoon of the mixture from the second tumbler and pour it back into the first tumbler. Which one of the following statements holds true ?**

a) There is less coffee in the first tumbler than water in the second tumbler.

b) There is more coffee in the first tumbler than water in the second tumbler.

c) There is as much coffee in the first tumbler as there is water in the second tumbler.

d) None of the statements holds true.

## View Answer and Explanation

Ans. c

Let us assume that spoon can contain 5 drops.

and tumbler can contain 100 drops.

Tumbler 1 –> Tumbler 2

(spoon contains 5w drops)

Tumbler 1: 95w

Tumbler 2: 100c + 5w

Tumbler 2 –> Tumbler 1

(spoon contains 4c+1w drops)

Tumbler 1 : 96w

Tumbler 2 : 96c

There is as much coffee in the first tumbler as there is water in the second tumbler.

**2. A mother, her little daughter and her just born infant boy together stood on a weighing machine which shows 74kgs. How much does the daughter weighs if themother’s weight is 46kg more than the combined weight of daughter and the infant and the infant weighs 60% less than the daughter.**

a) 9

b) 10

c) 11

d) None of these

## View Answer and Explanation

Ans. b

Let daughter’s weight be x.

Also, Infant’s weight is 60% less than daughter i.e 0.4x

Mother’s weight :

(x + 0.4x + 46)

Total weight = x + 0.4x + (x+0.4x+46) = 74

2.8x = 28

x = 10

**3. How many positive integers less than 4300 of digits 0 – 4.**

a) 560

b) 573

c) 574

d) None of these

## View Answer and Explanation

Ans. c

Let daughter’s weight be x.

Also, Infant’s weight is 60% less than daughter i.e 0.4x

Mother’s weight :

(x + 0.4x + 46)

Total weight = x + 0.4x + (x+0.4x+46) = 74

2.8x = 28

x = 10

**4. 100 students appeared for two different examinations 60 passed the first,50 the second and 30 both the examinations. Find the probability that a student selected at random failed in both the examination** ?

a) 5/6

b) 1/5

c) 1/7

d) 5/7

## View Answer and Explanation

Ans. b

Probability that a student selected failed in both exams :

100 – (60 + 50 – 30)/100

100 – 80/100

20/100

1/5

**5. It was the semester exam day, Vidhya caught the college bus. She enjoyed travelling by bus. Moving at 6 mph, the bus took Vidhya to college at the right time. She finished her exam and had a chit chat with her friends and suddenly she realized that it was 6 pm and she had missed the college bus. She decided to walk back home at 4 mph. What is her average speed for the day ?**

a) 4 mph

b) 5 mph

c) 2.4 mph

d) 4.8 mph

Ans. **(d)**

## View Answer and Explanation

Ans. d

Since distance is constant,

Average speed is given by 2xy/x+y

So,

(2*6*4)/(6+4) = 48/10 = 4.8mph.

I want solution for 155 question

Solution for Question 15:

The difference in 1 box = 45 – 27 = 18

Extra amount he has to pay to buy 27 boxes this year = 27 * 18 = 486$

Sol: 46

Let x, y & z be no of boxes George, Mark or Henry can paint in one day.

From given data,

20x + 20y = 720, ∴ x + y = 36 …(1)

24y + 24z = 720, ∴ y + z = 30 …(2)

15x + 15z = 720, ∴ x + z = 48 …(3)

Solving (1), (2) & (3),

x = 27

y = 9

z = 21

Now, to calculate no of boxes painted –

Boxes painted = 4x + 8y + 8z

Boxes painted = 4×27 + 8×9 + 8×21

Boxes painted = 108 + 72 + 168

Boxes painted = 348 boxes