Problem Statement
In this program we will code a basic program to reverse ‘n’ digit number in C programming language.
Code
#include<stdio.h>
int reverse(int n)
{
int rem=0,rev=0,num=0;
num=n;
while(num>0)
{
rem=num%10;
rev=rev*10+rem;
num=num/10;
}
return rev;
}
int main()
{
int n;
printf("Enter the number ?\n");
scanf("%d",&n);
int res=reverse(n);
printf("THE REVERSE OF %d IS : %d",n,res);
return 0;
}
Output
Enter the number ? – 453
THE REVERSE OF 453 IS : 354
Explanation
Let us consider an example :
Suppose we have to find the reverse of 235,we require three steps which needs to be performed under while loop condition (while n>0).
1 : Finding Remainder : rem=num%10
So, rem=235%10=5
2 : Finding Reverse : rev=rev*10+rem
So, rev=0+5
3 : Updating number : num=num/10;
So, num=23
But num>0, so we will perform above steps until ‘num’ gets equal to zero.After the last iteration we find rev=532.